A Seemingly Impossible Problem III
<p>Another <strong><span style="color:#8e44ad;">Seemingly Impossible Problem to Solve</span></strong>, this time with a trapezoid!</p>
<p><strong><span style="color:#e74c3c;">The Problem</span></strong></p>
<p>What is the area of the trapezoid below?</p>
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<p>What if we were to draw two perpendicular lines like so?</p>
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<p>Doing so splits up the base into three parts: $2$ (from above), and the remaining distance $5$, divided by $2$, to get two line segments of $2.5$ each.</p>
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<p>And now using our $45$-$45$-$90$ rules, we can find the height of the trapezoid (in red):</p>
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<p>To solve, use the area of a trapezoid formula:</p>
<p>$$\frac{2+7}{2} \times 2.5 = \frac{9}{2} \times 2.5 = 4.5 \times 2.5 = 11.25$$</p>