<p><a href="https://www.prepswift.com/quizzes/quiz/prepswift-permutations" target="_blank">Permutations Exercise</a></p><p>As discussed in the previous mountain entry, <strong><span style="color:#8e44ad;">Permutations</span></strong> are the number of arrangements where order is important.</p>
<p style="margin-left: 40px;"><strong><u>Tip</u></strong>: If you see a problem mention anything about "position," "ranking," "order," "arranged," or "arrangements," you're likely dealing with permutations.</p>
<p><strong><span style="color:#27ae60;">The Formula</span></strong></p>
<p>$$\frac{n!}{(n-r)!}$$</p>
<p style="text-align: center;"><em>where $n$ is the total number of elements and $r$ is the number of choices</em></p>
<p><strong><span style="color:#e74c3c;">Example From Previous Mountain Entry </span></strong></p>
<p style="margin-left: 40px;"><em>Five individuals enter a race that awards a different prize for 1st, 2nd, and 3rd place. In how many different ways can these awards be distributed?</em></p>
<p>Note that this is a problem dealing with "rankings," which tells us it's time to use the permutation formula where $n=5$ and $r=3$.</p>
<p>$$\frac{5!}{(5-3)!} = \frac{5!}{2!} = 5 \times 4 \times 3 = 60$$ </p>
<p><strong><span style="color:#2980b9;">Isn't This Just the Choice Method?</span></strong></p>
<p>Yeah, kind of. Notice if we solve the problem above using the "choice" method, we get the same answer:</p>
<p>$$5 \times 4 \times 3 = 60$$</p>
<p> </p>